Monday, August 17, 2020

Crime Math

I was shocked at how many people got this wrong. (via Bits and Pieces)

8 comments:

Anonymous said...

$100 less the profit margin on the $70 bong, that the thief wouldn't have bought if he hadn't stolen the money? So maybe $95 plus or minus?

Anonymous said...

$200 , the $100 stolen, the $70 pipe, and the $30 change. Not that hard

Harold said...

1. $100 stolen...owner is out $100 so far
2. $ 70 paid...owner is now out only $30 so far
3. $ 30 change...owner is now out $60 so far
4. $ 70 waterpipe out the door...owner is out $130 altogether.
- this $70 includes both the owner's cost for the pipe plus his profit margin.

Anonymous said...

One way to think of it is that the only theft that happens is the original $100. Everything after that looks like a regular transaction. The provenance of the money in that transaction is irrelevant as it already has been accounted for in the original theft.

Anonymous said...

$100.00.
Shop owner is even.
Guy steals $100.
Shop owner is at -$100.
Guy gives back the $100. Shop owner is even.
Shop owner gives the guy $70 item plus $30.
Shop owner is at -$100.

Debra She Who Seeks said...

The owner is out $500. Whaddya mean, I suck at math?

WilliamRocket said...

Lol. The guy is the focus point. He walks in with nothing, he walks out with $30 cash and an item worth $70. So the store owner loses $100, if we ignore what he paid for the pipe, et cetera. So C (what you Americans pronounce like Z)

ronnie b said...

$100 simples