Monday, August 17, 2020

Crime Math

I was shocked at how many people got this wrong. (via Bits and Pieces)

8 comments:

  1. $100 less the profit margin on the $70 bong, that the thief wouldn't have bought if he hadn't stolen the money? So maybe $95 plus or minus?

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  2. $200 , the $100 stolen, the $70 pipe, and the $30 change. Not that hard

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  3. 1. $100 stolen...owner is out $100 so far
    2. $ 70 paid...owner is now out only $30 so far
    3. $ 30 change...owner is now out $60 so far
    4. $ 70 waterpipe out the door...owner is out $130 altogether.
    - this $70 includes both the owner's cost for the pipe plus his profit margin.

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  4. One way to think of it is that the only theft that happens is the original $100. Everything after that looks like a regular transaction. The provenance of the money in that transaction is irrelevant as it already has been accounted for in the original theft.

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  5. $100.00.
    Shop owner is even.
    Guy steals $100.
    Shop owner is at -$100.
    Guy gives back the $100. Shop owner is even.
    Shop owner gives the guy $70 item plus $30.
    Shop owner is at -$100.

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  6. The owner is out $500. Whaddya mean, I suck at math?

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  7. Lol. The guy is the focus point. He walks in with nothing, he walks out with $30 cash and an item worth $70. So the store owner loses $100, if we ignore what he paid for the pipe, et cetera. So C (what you Americans pronounce like Z)

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